-+-Scriber-+-

hey everyone, i'm today's scribe. we started off class with our linear equations (graphing each equation) handed back. then Mrs. Ingram started us off with 3 example of changing an equation into the slope-intercept form.
Slope-Intercept form = y = mx + b
( m = slope, b = intercept )

The three examples were :
Change to the Slope-Intercept Form

Example Number 1.
1. 21y = 15 - 27x
= 21y/21 = -27x/21 + 15/21
= 7y/7 = -9/7 + 5/7
= y = -9/7 + 5/7

Step 1. ---> Change the equation to the Slope-Intercept Form.
Step 2.---> The first point on the graph, will be the y-intercept. (0, 5/7)
Step 3. ---> Locate the second point using the Slope. ( -9/7 = rise/run )

You then, should have a graph looking like this one;















Example Number 2.
2. 7x + 2y = -22
= 2y = -7x - 22
= 2y/2 = -7x/2 - 22/2
= y = -7/2 x - 11

You then, should end up with a graph looking like this;
















Example Number 3.
3. x = 7y/5 + 21/5
( you find the commen denominator and multiply everything by the commen denominator which is 5)
= 5x = 7y + 21
= 5x/7 - 21/7 = 7y/7
= 5x/7 - 3 = y

You then should have a graph looking like this;















If you had no problem and had a good understanding of those 3 examples then you would be just fine on the worksheet that was handed to us today in class.

Tonight's homework is the Linear Equation (Write the slope-intercept form of the equation). Do questions 4, 6, 12, 15, 16. Graph is to be handed in the beginning of tomorrows class.

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*drums...... tomorrows scribe will be NATASHA .. :O... wow no one expected that! "hahahah" good luck! =p