20S pre-cal

Saturday, March 04, 2006

Determining Equations of Lines

Today, March 03, 2006, Mrs. Ingram talked about determining the equations of lines, given two points. To explain how to solve these problems, I will use the second question from Exercise 15.
We were given two points, M(-2, 0) and N(4, 7).

* First, we should find the slope of the line that connects these two points.
Formula:
(Y2 - Y1) / (X2 - X1)
m = (7 - 0)/(4 + 2)
m = 7/6
* (/) = over
* Then, we can determine the equation of the line by substituting the values of one of the points (either one) and the slope into the point-slope formula.
Formula: (Y-Y1) = m (X - X1)
m = 7/6 point M (-2, 0)

(Y - 0) = 7/6 (X + 2)

y = (7x)/6 + 14/6

Right now, this equation is still in slope-intercept form. All we have to do now is to rearrange these values to turn it into the standard form.
6(y) = (7x/6 + 14/6)6
6y = 7x + 14
0 = 7x - 6y + 14

And there you go, now we’ve determine the equation of this line in standard form. Have a good weekend?
Cough * Wendy smells * Cough
well if you guys dont understand this its not my fault
You guys wanna hear a joke? *people cheer* Alright then here it goes: guess what ??? i bet your thinking about chicken butTS ROLFMAO ?HGAHAHA!!! jk..

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